Ngày đăng : 02/07/2022
ANSWER: The guidelines you see such as the you to your quote pertain just when the fees might be regarded as a continuous liquid that may pass on alone on one facial skin, regardless of what high, and then have no occurrence. Needless to say, a case like you explain, that have 5 extreme electrons is within no way eg a liquid and that i manage guess that everything from 5-0 in order to 0-5 is the delivery over a time. Theoretically, the 5 electrons perform plan by themselves making sure that for every single try while the well away on most other cuatro as possible, however, indeed there would not be a new like shipping.
QUESTION: Could it be possible to help you suspend a keen electron through electrostatic levitation into the good uniform magnetic occupation? While this new current try diminished enough so the electrostatic push on electron is less than the newest force due to the fresh electron's lbs perform the electron after that sense good 'fall' due in order to the law of gravity?
I am asking this because I'm wanting to know if place an excellent positron inside the an effective consistent magnetized community (in vacuum pressure) and you can lowering the voltage to a very small value so as that the new electrostatic push is gloomier compared to the lbs perform bring about an effective positron so you can as well as sense a beneficial 'fall'. Assuming it performed feel a fall it can be determined in the event it perform fall up otherwise down.
I'm 17 yrs old as well as in great britain about to data physics from the college in the september and you may was only interested in this just like the one of the subjects this present year is electronic phenomena and you may i discussed millikan's oil lose test hence checked a similar sorts of suspension if the electrostatic force and you will force because of the law of gravity had been healthy.
ANSWER: It is always nice to see young folks asking interesting questions. First, I need to correct one thing: everywhere you refer to a "magnetic field" you should say "electric field"; a magnetic field exerts no force on a charge at rest which is what you want to observe, la Millikan. (A more correct way, relativistically, to say this would be that they have equal momenta for equal speeds.) I believe it is true that nobody has ever "weighed" a positron by measuring the force it experiences in a gravitational field. But, if the gravitational mass were different from the inertial mass, this would fly in the face of the theory of general relativity. But, let's talk about the feasibility of your experiment. The mass of an electron is about 10 -30 kg so its weight would be about 10 -29 N (taking g?10 m/s 2 ). The electron charge is about 1.6x10 -19 C and so the electric field required to levitate an electron would be 10 -29 /1.6x10 -19 ?6x10 -11 V/m. Suppose we use a parallel plate capacitor to create this field. The charge density ? on a plate with field E is about ?=?0E?10 -11 x6x10 -11 =6x10 -22 C/m 2 which would correspond to an electron density on the plates of about 6x10 -22 /1.6x10 -19 ?0.004 electrons/m 2 ! This would correspond to about one electron for every 250 square meters! That would not give a very uniform field would it? There is no such thing as a uniform surface charge density because charges in nature do not comprise a continuous fluid; so really tiny uniform fields are not possible. I did all that just for the fun of it, but there is an even more serious considerationthe earth itself has an electric field near the surface of typically 100 V/m pointing down, so an electron would be repelled upward. To do your experiment you would have to get rid of that field and I do not believe that it would be possible to be assured that you could make the residual https://datingranking.net/asexual-dating/ field much less than your 6x10 -11 V/m. Back to the drawing board! Keep asking those hard and interesting questions, though, and good luck with your university studies.
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